X^2+6x-1287=0

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Solution for X^2+6x-1287=0 equation:



X^2+6X-1287=0
a = 1; b = 6; c = -1287;
Δ = b2-4ac
Δ = 62-4·1·(-1287)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-72}{2*1}=\frac{-78}{2} =-39 $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+72}{2*1}=\frac{66}{2} =33 $

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